Question

point S is any point on side QR of Triangle PQR .prove that : PQ+QR+RP greater than 2PS.
plz give me solution

Answer 1

to prove - AB + BC+CA> 2AS

proof:- in triangle ABS, 

  AB + BS > AS............ eqn1

  now,  In trianlge ACS, 

   AC + CS > AS......eqn 2

now from eqn 1 and 2 .. . 

we get. , 

     = AB + BS + AC+ CS > AS + AS

   = AB + BC + CA > 2AS ( BS + CS = BC) 

          = hence proved..  AB + BC + CA > 2AS..