Question

point S lies in the exterior of a circle with centre p and radius 33cm.A tangent from S touches the circle at T and ST=56 cm.find the distance of S from P.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

65 cm

Step-by-step explanation:

We are given that a circle with center P.

Radius of circle=33 cm

A point S lies in the exterior of a circle.

Length of tangent=ST=56 cm

We have to find the distance of S from P.

We know that radius is perpendicular to tangent.

Therefore, triangle PTS is a right triangle.

Pythagorous theorem

$(hypotenuse)^2=(base)^2+(perpendicular\;side)^2$

$PS^2=PT^2+ST^2$

$PS^2=(33)^2+(56)^2=4225$

$PS=\sqrt{4225}=65 cm$

Hence, the distance of S from P =65 cm