Math, asked by VijayaLaxmiMehra1, 1 year ago

Points A and B are 150 km apart on a highway. A car starts from A and another car starts from B simultaneously. If they travel in the same direction, they meet in 15 hours, but if they travel towards each other, they meet in 5 hours. Find the speed of the two cars.

( Ans : 20 km / h , 10 km / h )

Class 10

Content Quality Solution Required


#No Spams

Answers

Answered by NainaMehra
38
Hey!!


Refer to the attachment


Hope it helps ))
Attachments:

Cute111: Wah..kya answer diya hai... mjaa aa gya
Cute111: Mai apni baat kar rha hu..maine abhi abhi ek answer diya hai..
Answered by Anonymous
56

 \large{\mathfrak{HELLO \:  FRIENDS!!}}


 \large \bf{ \mathfrak{Here  \: is \:  your  \: answer↓}}


▶Let the speed of the cars from A and B be x km/hr and y km/hr respectively.




 \huge \boxed{CASE  \: 1.}

⏩ When the two cars move in the same direction:

In this case, let them at M after 15 hours.
[ See attachment 1. ]


Then, AM = 15x km.

And, BM = 15y km.


=> AM - BM = AB.

=> 15x - 15y = 150.

=> 15( x - y ) = 150.

 \huge \bf{=> x - y = 10...........(1).}



 \huge \boxed{CASE  \: 2.}

⏩When the two cars move in the opposite direction:


↪➡ Let one car move from A to B and let the other move from B to A. Let them meet at N after 5 hours.
[ See attachment 2.]

Then, AN = 5x km and BN = 5y km.

=> AN + BN = AB.

=> 5x + 5y = 150.

=> 5 ( x + y ) = 150.


 \huge \bf{=> x + y = 30..........(2).}


 \underline{Adding  \: equation \:  (1) \:  and \:  (2).}

x - y = 10.
x + y = 30.
(+)..(+)...(+).
________
2x = 40.

 \huge \boxed{=> x = 20.}

 \underline{Putting  \: x \:  in \:  equation \: ( 1).}

=> 20 - y = 10.

=> -y = 10 - 20.

=> - y = -10.

 \huge \boxed{=> y = 10.}


✅✅Hence, speed of car A = 20 km/hr.✔✔

✅✅Hence, speed of car B = 10 km/hr.✔✔



 \huge \large \boxed{ \mathfrak{THANKS}}



 \huge \large \bf \underline{ \mathfrak{Hope \:  it \:  is  \: helpful \:  for  \: you}}

Attachments:

fanbruhh: Nice one bhai
Anonymous: thanks bahna
BrainlyQueen01: Nice answer bhai :-)
Similar questions