Question

Points A,B,C are collinear such that d(A,B)= 18, d(B,C)=7, find d(A,C)​

Answer 1

Answer:

25 ...............

Step-by-step explanation:

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Answer 2

Find the distances with the help of the number line given below.

(i) d(B,E) (ii) d(J, A) (iii) d(P, C) (iv) d(J, H) (v) d(K, O)

(vi) d(O, E) (vii) d(P, J) (viii) d(Q, B)

ANSWER:

It is known that, distance between the two points is obtained by subtracting the smaller co-ordinate from larger co-ordinate.

(i) The co-ordinates of points B and E are 2 and 5 respectively. We know that 5 > 2.

∴ d(B, E) = 5 − 2 = 3

(ii) The co-ordinates of points J and A are −2 and 1 respectively. We know that 1 > −2.

∴ d(J, A) = 1 − (−2) = 1 + 2 = 3

(iii) The co-ordinates of points P and C are −4 and 3 respectively. We know that 3 > −4.

∴ d(P, C) = 3 − (−4) = 3 + 4 = 7

(iv) The co-ordinates of points J and H are −2 and −1 respectively. We know that −1 > −2.

∴ d(J, H) = −1 − (−2) = −1 + 2 = 1

(v) The co-ordinates of points K and O are −3 and 0 respectively. We know that 0 > −3.

∴ d(K, O) = 0 − (−3) = 0 + 3 = 3

(vi) The co-ordinates of points O and E are 0 and 5 respectively. We know that 5 > 0.

∴ d(O, E) = 5 − 0 = 5

(vii) The co-ordinates of points P and J are −4 and −2 respectively. We know that −2 > −4.

∴ d(P, J) = −2 − (−4) = −2 + 4 = 2

(viii) The co-ordinates of points Q and B are −5 and 2 respectively. We know that 2 > −5.

∴ d(Q, B) = 2 − (−5) = 2 + 5 = 7