Points D and E are marked on sides AC and BC, respectively. It is known that AB = BD, ∠ABD = 56∘, ∠DEC = 90∘. Find ∠BDE if it is known that 2DE = AD.
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Given : Points D and E are marked on sides AC and BC AB = BD, ∠ABD = 56∘, ∠DEC = 90∘ & 2DE = AD.
To find : ∠BDE
Solution:
in Δ ABD
AB = BD & ∠ABD = 56°
=> AD² = AB² + BD² - 2AB.BDCos56°
=> AD² = BD² + BD² - 2BD²Cos56°
=> AD² = 2BD² (1 - Cos56°)
=> AD² = 2BD² (2Sin²28°)
=> AD = 2BDSin28°
2DE = AD
=> 2DE = 2BDSin28°
=> DE/BD = Sin28°
∠DEC = 90° => ∠DEB = 90° as E is on BC
in Δ DEB
Sin∠DBE = DE/BD
=> Sin∠DBE = Sin28°
=> ∠DBE = 28°
∠BDE + ∠DBE + ∠DEB = 180°
=> ∠BDE + 28° + 90° = 180°
=> ∠BDE = 62°
∠BDE = 62°
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