polar form of -1+√3i
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Step-by-step explanation:
r=|z|=√(-1)²+(√3)²
=2
tan alpha=√3
alpha=Π/3
since θ lies in the II quadrent
Π-alpha
amp=Π-Π/3
amp=2Π/3
polar form is
r(cosθ+isinθ)
=2(cos2Π/3+isin2Π/3)
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