Question

Polar form of circle with radius 2 and centre (0,2) is

Answer 1

(X-0)2 +(Y-2)2=(2)2
Therefore
X2 +Y2 - 4Y=0

Answer 2

Answer:

Equation of circle in polar form is given by

$r=4\sin\theta$

Step-by-step explanation:

The equation of a circle in Cartesian form is give  by

$(x-h)^2+(y-k)^2=r^2$

Here, (h,k) is the center and r is the radius.

Thus, equation of circle is

$(x-0)^2+(y-2)^2=2^2\\x^2+y^2-4y+4=4\\\\x^2+y^2-4y=0$

In polar coordinates, we know

$x=r\cos\theta,y=r\sin\theta,x^2+y^2=r^2$

Thus, the equation of circle in polar form is given by

$r^2-4r\sin\theta=0\\\\r=4\sin\theta$