Question

pole of f(z) = (tan(z/2))/z-(1+i)^2 is (1+i) is a pole of order. a) 0 b) 2 c) undefined d) none​

Answer 1

Answer:

0

Step-by-step explanation:

The residue of

f(z)=tanz

at any of its pole is,

f(z)=tanz=(z−π2)(tanz)(z−π2)

(Resf(z)=tanz;z=π2)=limz→π2((z−π2)(tanz))=0