poles of a horse shoe magnet each of pole strength 2A m are 4 cm apart . The magnetic induction at the mid point between the poles is
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Given:
Pole strength of the horse shoe magnet = 2A
Difference between the poles of the horse shoe magnet = 4 cm
To find:
Magnetic induction at the mid point between the poles.
Solution:
- Let Bn denotes the magnitude of the magnetic field due to N-pole and Bs denotes the magnitude of the magnetic field due to S-pole.
- Thus, at the mid point (O) magnetic field will be (Bnet) = Bn + Bs
- Also, Bn = Bs = μ₀m / 4πr²
= (4π x 10⁻⁷ x 2) / 4π (0.04 / 2)²
= 5 x 10⁻⁴
- And Bnet = 2x(5 x 10⁻⁴) = 10 x 10⁻⁴
- The magnetic induction at the midpoint between the pole will be 10 x 10⁻⁴.
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