Question

POLYNOMA
1. Find the zeroes of the following quadratic polynomials and verify the relationship between
the zeroes and the coefficients.
1) x2 - 2x -8
(ii) 482-4s + 1
(iii) 6x2 – 3-7x
(iv) 4u²+ 8u
(v) 12 - 15
(vi) 3x2 - x - 4
each with the given numbers as the sum and product of its​

Answer 1

Step-by-step explanation:

1. $x {}^{2} - 2x - 8 = x {}^{2} - 4x + 2x - 8 \\ {x}(x - 4) + 2(x - 4) \\ = (x - 4)( x + 2) \\ zeroes \: = 4 \: and \: - 2 \\ sum \: = - b \div a \\ = - ( - 2 \div 1) \\ = 2 = 4 + - 2$