Question

polynomial find zero
x²+7x-18 ​

Answer 1

Step-by-step explanation:

${x}^{2} + 7x - 18 \\ {x}^{2} + 9x - 2x - 18 \\ x(x + 9) - 2(x + 9) \\ (x - 2)(x + 9) \\ \\ x - 2 = 0 \\ x = 2 \\ \\ x + 9 = 0 \\ x = - 9$

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Answer 2

Answer:

x=2 and x= -9 are the zeroes of the polynomial.

Step-by-step explanation:

$\begin{gathered} {x}^{2} + 7x - 18 = 0 \\ {x}^{2} + 9x - 2x - 18 = 0\\ x(x + 9) - 2(x + 9) = 0\\ (x - 2)(x + 9) = 0\\ \\ x - 2 = 0 \\ x = 2 \\ \\ x + 9 = 0 \\ x = - 9\end{gathered}</p><p></p><p>$

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