Math, asked by priyanshu1392, 1 year ago

Polynomial identities for std 9th

Answers

Answered by parvd
4

Answer:

hey mate!!

=============

Step-by-step explanation:

============================

IDENTITIES ARE LIKE THIS PRYANSHU :)

----------------------------------------------------------

Polynomial identities for std 9th

a+b) 2 = a 2 + 2ab + b 2

(a+b)(c+d) = ac + ad + bc + bd

a 2 - b 2 = (a+b)(a-b) (Difference of squares)

a 3 (+-) b 3 = (a (+-) b)(a 2(-+) ab + b 2) (Sum and Difference of Cubes)

x 2 + (a+b)x + AB = (x + a)(x + b)

if ax 2 + bx + c = 0 then x = ( -b (+-)sqrt(b 2 - 4ac) ) / 2a (Quadratic Formula)

Answered by kunalmakhija
1

(a+b)2

(a-b)2

(a2+b2)

(a2-b2)

etc .. even more........

Similar questions