Polynomial identities for std 9th
Answers
Answered by
4
Answer:
hey mate!!
=============
Step-by-step explanation:
============================
IDENTITIES ARE LIKE THIS PRYANSHU :)
----------------------------------------------------------
Polynomial identities for std 9th
a+b) 2 = a 2 + 2ab + b 2
(a+b)(c+d) = ac + ad + bc + bd
a 2 - b 2 = (a+b)(a-b) (Difference of squares)
a 3 (+-) b 3 = (a (+-) b)(a 2(-+) ab + b 2) (Sum and Difference of Cubes)
x 2 + (a+b)x + AB = (x + a)(x + b)
if ax 2 + bx + c = 0 then x = ( -b (+-)sqrt(b 2 - 4ac) ) / 2a (Quadratic Formula)
Answered by
1
(a+b)2
(a-b)2
(a2+b2)
(a2-b2)
etc .. even more........
Similar questions