polynomial of 3x^2-4x^2-3x-1 by x-1 divide
Answers
Answered by
0
Answer:
let p(x)=3x²-4x²-3x-1
g(x)=x-1
BY REMAINDER THEROM,
the zero of the polynomial( x-1) is 1
so,p(1)=3(1)²-4(1)²-3(1)-1
=3-4-3-1
=-5
Answered by
0
Answer:
-5
Step-by-step explanation:
p(x)=3x^2-4x^2-3x-1
x-1
x=1
p(1)=3(1)^2-4(1)^2-3(1)-1
=3-4-3-1
=-5
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