Math, asked by navjotsingh85910059, 4 months ago

polynomial of 3x^2-4x^2-3x-1 by x-1 divide​

Answers

Answered by zaheerask1985
0

Answer:

let p(x)=3x²-4x²-3x-1

g(x)=x-1

BY REMAINDER THEROM,

the zero of the polynomial( x-1) is 1

so,p(1)=3(1)²-4(1)²-3(1)-1

=3-4-3-1

=-5

Answered by sainlab1980
0

Answer:

-5

Step-by-step explanation:

p(x)=3x^2-4x^2-3x-1

x-1

x=1

p(1)=3(1)^2-4(1)^2-3(1)-1

=3-4-3-1

=-5

Similar questions