Polynomial with zeros 1 and I are
k (x2 - 1)
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Answered by
2
Answer:
Given : One of the zeros of quadratic polynomial (k−1)x
2
+kx+1 is −3
To find : Value of k
Solution : As −3 is one of the zeros of quadratic polynomial (k−1)x
2
+kx+1
⇒ When we substitute −3 in the polynomial , we get 0
⟹(k−1)(−3)
2
+k(−3)+1=0
⟹9k−9−3k+1=0
⟹6k−8=0
or k=
6
8
=
3
4
Answered by
0
Answer:
once check whether all the spelling in the given question ❓ are spelled correctly or not
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