Question

polynomials formulas only 10th class
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Answer 1

Answer:

The general Polynomial Formula is written as,

The general Polynomial Formula is written as,axn+bxn−1+…..+rx+s

The general Polynomial Formula is written as,axn+bxn−1+…..+rx+sIf n is a natural number, an – bn = (a – b)(an-1 + an-2b+…+ bn-2a + bn-1)

The general Polynomial Formula is written as,axn+bxn−1+…..+rx+sIf n is a natural number, an – bn = (a – b)(an-1 + an-2b+…+ bn-2a + bn-1)If n is even (n = 2k), an + bn = (a + b)(an-1 – an-2b +…+ bn-2a – bn-1)

The general Polynomial Formula is written as,axn+bxn−1+…..+rx+sIf n is a natural number, an – bn = (a – b)(an-1 + an-2b+…+ bn-2a + bn-1)If n is even (n = 2k), an + bn = (a + b)(an-1 – an-2b +…+ bn-2a – bn-1)If n is odd (n = 2k + 1), an + bn = (a + b)(an-1 – an-2b +…- bn-2a + bn-1)

The general Polynomial Formula is written as,axn+bxn−1+…..+rx+sIf n is a natural number, an – bn = (a – b)(an-1 + an-2b+…+ bn-2a + bn-1)If n is even (n = 2k), an + bn = (a + b)(an-1 – an-2b +…+ bn-2a – bn-1)If n is odd (n = 2k + 1), an + bn = (a + b)(an-1 – an-2b +…- bn-2a + bn-1)(a + b + c + …)2 = a2 + b2 + c2 + … + 2(ab + ac + bc + ….

The general Polynomial Formula is written as,axn+bxn−1+…..+rx+sIf n is a natural number, an – bn = (a – b)(an-1 + an-2b+…+ bn-2a + bn-1)If n is even (n = 2k), an + bn = (a + b)(an-1 – an-2b +…+ bn-2a – bn-1)If n is odd (n = 2k + 1), an + bn = (a + b)(an-1 – an-2b +…- bn-2a + bn-1)(a + b + c + …)2 = a2 + b2 + c2 + … + 2(ab + ac + bc + ….Solved Examples

The general Polynomial Formula is written as,axn+bxn−1+…..+rx+sIf n is a natural number, an – bn = (a – b)(an-1 + an-2b+…+ bn-2a + bn-1)If n is even (n = 2k), an + bn = (a + b)(an-1 – an-2b +…+ bn-2a – bn-1)If n is odd (n = 2k + 1), an + bn = (a + b)(an-1 – an-2b +…- bn-2a + bn-1)(a + b + c + …)2 = a2 + b2 + c2 + … + 2(ab + ac + bc + ….Solved ExamplesQuestion 1: What are the factors of the equation x2 – 10x + 25 ?

The general Polynomial Formula is written as,axn+bxn−1+…..+rx+sIf n is a natural number, an – bn = (a – b)(an-1 + an-2b+…+ bn-2a + bn-1)If n is even (n = 2k), an + bn = (a + b)(an-1 – an-2b +…+ bn-2a – bn-1)If n is odd (n = 2k + 1), an + bn = (a + b)(an-1 – an-2b +…- bn-2a + bn-1)(a + b + c + …)2 = a2 + b2 + c2 + … + 2(ab + ac + bc + ….Solved ExamplesQuestion 1: What are the factors of the equation x2 – 10x + 25 ?Solution:

The general Polynomial Formula is written as,axn+bxn−1+…..+rx+sIf n is a natural number, an – bn = (a – b)(an-1 + an-2b+…+ bn-2a + bn-1)If n is even (n = 2k), an + bn = (a + b)(an-1 – an-2b +…+ bn-2a – bn-1)If n is odd (n = 2k + 1), an + bn = (a + b)(an-1 – an-2b +…- bn-2a + bn-1)(a + b + c + …)2 = a2 + b2 + c2 + … + 2(ab + ac + bc + ….Solved ExamplesQuestion 1: What are the factors of the equation x2 – 10x + 25 ?Solution:x2 – 10x + 25

The general Polynomial Formula is written as,axn+bxn−1+…..+rx+sIf n is a natural number, an – bn = (a – b)(an-1 + an-2b+…+ bn-2a + bn-1)If n is even (n = 2k), an + bn = (a + b)(an-1 – an-2b +…+ bn-2a – bn-1)If n is odd (n = 2k + 1), an + bn = (a + b)(an-1 – an-2b +…- bn-2a + bn-1)(a + b + c + …)2 = a2 + b2 + c2 + … + 2(ab + ac + bc + ….Solved ExamplesQuestion 1: What are the factors of the equation x2 – 10x + 25 ?Solution:x2 – 10x + 25= x2 – 2(5x) + 52

The general Polynomial Formula is written as,axn+bxn−1+…..+rx+sIf n is a natural number, an – bn = (a – b)(an-1 + an-2b+…+ bn-2a + bn-1)If n is even (n = 2k), an + bn = (a + b)(an-1 – an-2b +…+ bn-2a – bn-1)If n is odd (n = 2k + 1), an + bn = (a + b)(an-1 – an-2b +…- bn-2a + bn-1)(a + b + c + …)2 = a2 + b2 + c2 + … + 2(ab + ac + bc + ….Solved ExamplesQuestion 1: What are the factors of the equation x2 – 10x + 25 ?Solution:x2 – 10x + 25= x2 – 2(5x) + 52= x2 – 2(5)(x) + 52

The general Polynomial Formula is written as,axn+bxn−1+…..+rx+sIf n is a natural number, an – bn = (a – b)(an-1 + an-2b+…+ bn-2a + bn-1)If n is even (n = 2k), an + bn = (a + b)(an-1 – an-2b +…+ bn-2a – bn-1)If n is odd (n = 2k + 1), an + bn = (a + b)(an-1 – an-2b +…- bn-2a + bn-1)(a + b + c + …)2 = a2 + b2 + c2 + … + 2(ab + ac + bc + ….Solved ExamplesQuestion 1: What are the factors of the equation x2 – 10x + 25 ?Solution:x2 – 10x + 25= x2 – 2(5x) + 52= x2 – 2(5)(x) + 52= (x – 5)2

Hope this Answer helps you to Gain Knowledge about Polynomial Formula