population doubles every 10 years, find the percentage increase in population from 1979 to 2009
Answers
Answered by
6
Let the population in 1979 = P
time = 2009-1979 = 30 years.
Population doubles in 10 years.
So population after 30 years =

Increase in population = 8P - P = 7P
% increase = 7P/P × 100 = 700%
time = 2009-1979 = 30 years.
Population doubles in 10 years.
So population after 30 years =
Increase in population = 8P - P = 7P
% increase = 7P/P × 100 = 700%
Answered by
4
Let in 1979 population = x
then in 2009= 8x
and proceed.
then in 2009= 8x
and proceed.
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