Math, asked by kavita4136, 9 months ago

Population of a town increase by 10% annually. If present population is 60,000. What will be the population after 2 years.
What was it a year ago.

Answers

Answered by merinmathew232
2

Answer:

Population after 2 years = 72,000

Population a year ago = 54,000

Step-by-step explanation:

Given present population = 60,000

Annual increase in population = 10%

Population after 2 years = 60,000 +20% of 60,000

                               = 60,000 + 20/100 × 60,000

                               = 60,000 + 12,000= 72,000

Population a year ago = 60,000 - 10% 0f 60,000

                                   = 60,000 - 10/100 × 60,000

                                   = 60,000 - 6,000= 54,000

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