Question

population of city in a specific year was 80000 there was rise of 10% for each of next 2 years find the population at end of 2 years

Answer 1

hey mate
here's the solution

Answer 2

Answer is 96800.

Solution is

10 % of 80000 is = 8000

Formula

$\% = total \: ammount \: \times preset \: \div 100$

$80000 \times 10 \div 100 = 8000$
Then 1st year population is 80000+8000 = 88000

Then next year population is

10 % of 88000

Formula
$88000 \times 10 \div 100 = 8800$
This year total population is
88000 + 8800 = 96800

The answer is 96800.

I hope it's helpful for you. Thank you