Population of city increased 4 percent every year if it's Population today is 1500000 what was its Population 3 year back
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Let the population of the town after 2 years be x
Increase percent of population every year = 10%
Present population = 180000
= 10% of 180000
= 10/100 * 180000 = 10*1800 = 18000
Increase in population after 1 year = 180000+18000 = 198000
Increase in population afer 2 years = 10% of population in 1 year + population of 1 year
= 10% of 198000+198000
= 10/100 * 198000 = 10*1980 = 19800
= 198000+19800 = 217800
Therefore, the population of the town after 2 years is 2,17,800.
Answered by
1
You can get the solution from the solution in the pic.
P = Old population
R = Rate of change
T = Time
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