Question

Population of city increases 10% every year over its previous year present population 266200 three years ago population

Answer 1

ANSWER:

The population of the city three years ago was 2,00,000

EXPLANATION:

Given:  

Rate of Increase of Population = 10%

Present population (A ) = 2662000

Number of years = 3

To find:

The population present 3 years ago

Solution:

Let the population 3 years ago be P

$A=P \times\left(1+\frac{R}{100}\right)^{3}$

Now substitute the value of P and R, we get,

$2,66,200=P \times\left(1+\frac{10}{100}\right)^{3}$

Now, take L.C.M., we get,

$2,66,200=P \times\left(\frac{110}{100}\right)^{3}$

$\frac{2,66,200 \times 100 \times 100 \times 100}{110 \times 110 \times 110}=P$

$\therefore P=2,00,000$

Therefore, the population of the city three years ago was found to be 2,00,000