Question

Population of the town is increased by 6% per annum it was 238765 in the year 2018 find the population in the year 2016 and 2020

Answer 1

Answer:in the year. 2016= 212500 and in 2020 is 268276.35

Step-by-step explanation:

Answer 2

Population was in the 2016 :

$238765 \times \frac{100}{(100 + 6)} \times \frac{100}{(100 + 6)} \\ \\ = > 238765 \times \frac{100}{106} \times \frac{100}{106} = 212500$

And, population will be in 2020 :

$238765 \times \frac{(100 + 6)}{100} \times \frac{(100 + 6)}{100} \\ \\ = > 238765 \times \frac{106}{100} \times \frac{106}{100} = 268276.354$

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