Question

position of a body related to time is given by x=(16t + 4t^2)×2 ,x is in m,t is in s. Find acceleration of the body when velocity is 100 m/s. also find distance traveled by a body in 3 seconds​

Answer 1

Answer:

Correct option is

A

5 m

The correct option is A.

Given,

x=t

2

−4t+6

So, the change in velocity is:

dt

dx

=2t−4

Since velocity is changing,

At t=0,x

1

=6

At t=2,x

2

=2

So the magnitude of the distance traveled is:

6−2=4m

At t=3,x

3

=3

So distance traveled from t=2s to t=3s

x

3

−x

2

=3−2=1m

Thus the total distance is:

4+1=5m

Answer 2

Answer:

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