Question

Position of a particle moving on a straight line is x=t^3-3t^2+8t+4.consider mption of a particle from t=0 to t=5 seconds.let s1 be the total distance travelled and s2 be the distance travelled during retardation,then s1/s2=

Answer 1

do in eqn taking t=0 we get, x= 4
now at t=5 , x= 94 so s1= 90
now v= 3t^2-3t+8
so a= 6t-3
t=0 a= -3 and at t=5 a= 27
but at t= 1/2 a=0 so s2= 1/8-3/4+8
then find s1/s2