Question

position of a particle s = 3x^2 +2x^4+3x, where x is the time period of the body . find the velocity and the acceleration of the body if x=4 sec​

Answer 1

The displacement is given as x=5t

2

+4t+3

⇒x−3=5t

2

+4t

assuming x−3=s,

s=4t+

2

1

10t

2

comparing this with s=ut+

2

1

at

2

we get u=4m/s and a=10m/s

2

so velocity at t=2sec is v=u+at=4+10×