Question

Position time graph of a body of mass 5 kg is
given in the diagram. The impulse on body a
t =
3 S,
is
x(m)
18+
12-
1 2 3
4
5 tis)​

Answer 1

impulse on body at (t = 3s) is -30 Kgm/s

we have given position time graph. in this graph it is clear that, velocity during 0s to 3s is slope of it.

i.e., initial velocity of body, u = 18/3 = 6 m/s

after 3s we see position time graph is straight line parallel to x-axis (time ). it means velocity t≥ 3s will be zero.

then, final velocity of body, v = 0 m/s

now impulse = change in momentum

= m(v - u)

= 5kg × (0m/s - 6 m/s)

= -30 Kgm/s

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Answer 2

The impulse on body is -30 kg-m/s

Explanation:

Please see the attachment for figure.

Impulse = Change in momentum

Momentum = mass × velocity

From position-time graph. The slope of line gives velocity of body.

• For time interval: (0,3)

Slope change is initial velocity of body, u

$u=\dfrac{18-0}{3-0}=6\ m/s$

• For time interval: (3,7)

Slope change is final velocity of body, v

$v=\dfrac{18-18}{7-3}=$0

Mass of body, m = 5 kg

Change in momentum = mv - mu

                                     = 5(0-6)

                                     = -30 kg-m/s

Impulse = Change in momentum

Impulse = -30 kg-m/s

#Learn more:

Impulse of a body

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