Physics, asked by Parveenmubeen140, 1 year ago

Two spheres A & B of radius 4cm and 6cm are given charges of 80microcoulomb & 40microCoulomb respectively.If they are connected by a fine wire,the amount of charge flowing from one to the other is..?​

Answers

Answered by susmitabehera2004
8

Explanation:

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Answered by CarliReifsteck
5

Given that,

Radius of sphere A = 4 cm

Radius of sphere B = 6 cm

Charge of A = 80 μC

Charge of B = 40 μC

We know that,

The charge is inversely proportional to the radius of the sphere.

q\propto\dfrac{1}{r}

We need to calculate the amount of charge flowing from one to the other

Using relation of charge and radius

q_{1}r_{1}=q_{2}r_{2}

Put the value into the formula

80\times10^{6}\times4=q_{2}(4+6)

q_{2}=\dfrac{80\times10^{6}\times4}{0}

q_{2}=32000000\ C

q_{2}=32\ \mu C

Hence, The amount of charge flowing from one to the other is 32 μC.

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