Question

Two spheres A & B of radius 4cm and 6cm are given charges of 80microcoulomb & 40microCoulomb respectively.If they are connected by a fine wire,the amount of charge flowing from one to the other is..?​

Answer 1

Explanation:

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Answer 2

Given that,

Radius of sphere A = 4 cm

Radius of sphere B = 6 cm

Charge of A = 80 μC

Charge of B = 40 μC

We know that,

The charge is inversely proportional to the radius of the sphere.

$q\propto\dfrac{1}{r}$

We need to calculate the amount of charge flowing from one to the other

Using relation of charge and radius

$q_{1}r_{1}=q_{2}r_{2}$

Put the value into the formula

$80\times10^{6}\times4=q_{2}(4+6)$

$q_{2}=\dfrac{80\times10^{6}\times4}{0}$

$q_{2}=32000000\ C$

$q_{2}=32\ \mu C$

Hence, The amount of charge flowing from one to the other is 32 μC.