position vector of A is a and B is b. let C be the point that cuts AB externally. proved that AC=3AB
Answers
Answered by
0
Step-by-step explanation:
Answer
Let position vector of C=
c
Let position vector of D=
d
AC
=
c
−
a
AB
=
b
−
a
BD
=
d
−
b
BA
=
a
−
b
AC=3AB
⇒
c
−
a
=3(
b
−
a
)
⇒
c
−
a
=3
b
−3
a
⇒
c
=3
b
−2
a
⇒
BD
=2
BA
⇒
d
−
b
=2(
b
−
a
)
⇒
d
−
b
=2
b
−2
a
⇒
d
=3
b
−2
a
Similar questions