Question

position x of a particle is given by x= Bt^2 + C/Bt
what are dimensions of C? , x in meters, t in seconds

Answer 1

Answer:

X=Bt2 +C/Bt

X=L

L=Bt^2

B =LT^-2

x has same dimensions as of Bt^2 and C/Bt ie L

X= C/[LT^-2]T

C= L^2T^-1