Question

Position x of a particle moving alone a straight line with time t is given by x= under root t2+2 find acceleration

Answer 1

In this question, we are given x as a funtion of time,

i.e. F(x) = $\sqrt{t^{2} + 2 }$

easily, by differentiating this equation we can get the velocity of the body,

$\frac{dx}{dt} =  \frac{t^{3}}{2}$

Once again differentiation the above expression we will get the acceleration,

$\frac{dv}{dt} = \frac{3}t^{2} {2}$

Best of Luck!!

SamSax.