position (x) of particle vary with time t = ax²+bx then acceleration is equal to?
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displacement=f(x)=ax²+bx
velocity=f'(x)=2ax+b
acceleration=f''(x)=2a
velocity=f'(x)=2ax+b
acceleration=f''(x)=2a
deepa63:
this is not correct
what is correct?
correct answer is. -2xv³
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