if x^2+1/x^2=38 then find the value of x ^3-1/x^3
Answers
Answered by
76
x²+1/x²=38
x²+1/x²-2=38-2(subtracting 2 from both sides)
(x-1/x)²=36
x-1/x=±6
x³-1/x³=(x-1/x)(x²-x×1/x+1/x²)
(±6)(38-1)
±6×39
±234
mark me as brain list
x²+1/x²-2=38-2(subtracting 2 from both sides)
(x-1/x)²=36
x-1/x=±6
x³-1/x³=(x-1/x)(x²-x×1/x+1/x²)
(±6)(38-1)
±6×39
±234
mark me as brain list
Answered by
27
Answer:
Step-by-step explanation:
Attachments:
Similar questions