Question

positive solution of these equation by trail and improvement x²- x=60​

Answer 1

${x}^{2} - x = 60$

$= > {x}^{2} - x - 60 = 0$

$by \: quadratic \: formula$

$x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a}$

$= > x = \frac{ - ( - 1)± \sqrt{ ({ - 1})^{2} \: - \: \:4 \times 1 \times ( - 60)} }{2 \times 1}$

$= > x = \frac{1± \sqrt{1 + 240} }{2}$

$= > x = \frac{1± \sqrt{241} }{2}$

$so \: its \: positive \: value \: is -$

$\frac{1 + \sqrt{241} }{2}$

hope it helps

Answer 2

Answer:

what are you doing arsala