POT) and (2) for each of the following polynomials p(X)=x2-x+1
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Answer:
Given polynomial f(x)=px+q
we know that for zero polynomial f(x)=0
px+q=0
px+q−q=−q
⇒px=−q
x=−
p
q
(because p
=0,pq are real number )
Then for value of x is −
p
q
the polynomial is zero polynomial
Step-by-step explanation:
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