Potassium hydroxide and chloroform reaction
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When chloroform reacts with aq. KOH, the chlorines on the carbon atom are successively replaced by -OH groups from KOH via. nucleophilic reaction (SN2). In theory, first it forms CHCl2(OH), then CHCl(OH2), and then CH(OH)3, while eliminating KCl with each step. Since Cl- is an excellent leaving group, CHCl(OH2) will spontaneously release one molecule of H2O and produce HC(=O)Cl or formyl chloride, which again will be hydrolyzed to produce HCOOK or Potassium Formate.
1 mole of Chloroform will react with 4 moles of KOH to produce 1 mole of HCOOK (potassium formate), 3 moles of KCl and 2 moles of H2O.
1 CHCl3 + 4 KOH —-> HCOOK + 3 KCl + 2 H2O.
1 mole of Chloroform will react with 4 moles of KOH to produce 1 mole of HCOOK (potassium formate), 3 moles of KCl and 2 moles of H2O.
1 CHCl3 + 4 KOH —-> HCOOK + 3 KCl + 2 H2O.
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