Question

Potential at d point in the given circuit is

Answer 1

Given:

The voltage in the circuit is V= 6V

The four resistance are 2,2,2,2 Ω

To find:

The potential at point D

Solution:

The total resistance in the circuit is R=2+2+2+2

R= 8 Ω

The ohm' formula

V=I×R

I=$\frac{V}{R}$

I=$\frac{6}{8}$ A

As the current remains same in series

Therefore the potential at point D be

V= $\frac{6}{8}$×2

V=$\frac{6}{4}$ V

The potential at D is V=$\frac{6}{4}$ V

Answer 2

Explanation:

answer voltage at point D is (-2 volt)