Physics, asked by TristAnnie5856, 1 year ago

Potential at the edge of disc

Answers

Answered by ommprasadnayak2004

0

(c) 4σkR

Explanation : dV=kdqr

dq=σ(2rθ)dr

dV=14π∈0σ2rdrθr=σ2π∈0θdr

r=2Rcosθ

r=2Rcosθ

dr=−2Rsinθdθ

dr=−σ2π∈02Rθsinθdθ

V=∫0π2dV=σRπ∈0∫π20θsinθdθ

V=σRπ∈0=4kσR.

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