Question

potential energy of 100 kg block 10 m along a 30* inclined plane???

Answer 1

Dear Student,

◆ Answer -

PE = 4900 J

● Explaination -

# Given -

m = 100 kg

s = 10 m

θ = 30°

# Solution -

Potential energy on inclined plane is given by -

PE = m × g × h

PE = m × g × s.sinθ

PE = 100 × 9.8 × 10 × sin30°

PE = 9800 × 0.5

PE = 4900 J

Therefore, potential energy of the block will be 4900 J at inclined plane.

Hope that is helpful to you...