potential energy of a body of mass 0.5 kg increases by 100 J when it is taken to the top of the tower from ground If force of gravity on 1kg is 10 N what is the what is the height of tower
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16
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Force of gravity on 1kg is 10 N
F = mg
10 = 1 * g
g = 10 m/s^2
Change in Potential energy = mg * ( h2 - h1 )
= mg * ( h - 0 )
= mgh
100 = mgh
h = 100 / mg
h = 100 / (0.5 * 10)
h = 20 m
Height of the tower is 20 m
I HOPE IT HELPS U.
HERE IS UR ANSWER.
Thanks for asking this question.
Force of gravity on 1kg is 10 N
F = mg
10 = 1 * g
g = 10 m/s^2
Change in Potential energy = mg * ( h2 - h1 )
= mg * ( h - 0 )
= mgh
100 = mgh
h = 100 / mg
h = 100 / (0.5 * 10)
h = 20 m
Height of the tower is 20 m
I HOPE IT HELPS U.
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15
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