Question

potential energy of a particle at position x is given by U = x2 - 5x. Which of the following is equilibrium position
Potential energy of a parti
of the particle?​

Answer 1

Answer:

U=x^2 -5x. (eq (1))

on differentiation

U = 2x-5=0

2x=5

x=5/2

putting value of x in eq (1)

U = (5/2)^2 - 5*5/2

U = 25/2 - 25/2 = 1

It is stable equilibirm .

Answer 2

Answer:

x=2.5

hope it helps you...