Question

Potential energy of a two particle system separated by a distance r is given by U(r)=A/r where A is a
Constant. Find the radial force F. that each particle exerts on the other.
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Answer 1

Answer:

The force that each particle exerts radially over each other is $\frac{A}{r^2}$

Explanation:

Given the potential energy

$U=\frac{A}{r}$

The radial force between the particles is given by

$\boxed{F=-\frac{dU}{dr}}$

$\implies F=-\frac{d}{dr}(\frac{A}{r})$

$\implies F=-A(-r^{-2})$

$\implies F=\frac{A}{r^2}$

Therefore, the force that each particle exerts radially over each other is $\frac{A}{r^2}$

Hope this answer is helpful.