Question

Potential energy of an electron in the hydrogen atom is -6.8ev indicate in which excited state the electron is present

Answer 1

Answer: First excited state(n=2)

Explanation:

PE= 2*Total Energy

TE= -3.4eV

TE= -13.6 * z²/n²

z of H atom is 1

Thus, -13.6/n² =-3.4

n²=4

n=2