Question

Power dissipated across resistor X with explanation .... as fast as possible... answer it from the 4 options given in the pic....
PLZZ ANSWER MY QUES...

Answer 1

first the total resistance must be taken into account

the total resistance is equal to

3 ohm + 3 ohm + 3 ohm + 3 ohm = 12 ohm.

voltage = 1.5

therefore the current drawn is = 1.5/12 = .125 A

we know that current = power / voltage

power = current * voltage = .125 * 1.5 = .1875 watt

therefore the power that is dissipated = .1875

therefore the correct answer is option 2

plz mark as brainliest

byee

Answer 2

3 Ohms + 3 Ohms = 6 Ohms  

3 Ohms + 3 Ohms = 6 Ohms  

The fifth resistor is parallel with the  

two 6 Ohms series combinations.  

1/Re = 1/6+1/6+1/3 =1/6+1/6+2/6 = 4/6  

1/Re = 2/3  

Re = 1.5  

Total current = 1.5V/1.5Ohms = 1 Ampere  

.5 Amperes through 6 Ohms parallel 6 Ohms  

.5 Amperes through 3 Ohms  

Each 6 Ohm series combination carries .25 Amperes.  

Power = I²×R = (.25)²×3 = .1875 Watts  

(Answer: (2) 0.187 W) 3 Ohms + 3 Ohms = 6 Ohms  

3 Ohms + 3 Ohms = 6 Ohms  

The fifth resistor is parallel with the  

two 6 Ohms series combinations.  

1/Re = 1/6+1/6+1/3 =1/6+1/6+2/6 = 4/6  

1/Re = 2/3  

Re = 1.5  

Total current = 1.5V/1.5Ohms = 1 Ampere  

.5 Amperes through 6 Ohms parallel 6 Ohms  

.5 Amperes through 3 Ohms  

Each 6 Ohm series combination carries .25 Amperes.  

Power = I²×R = (.25)²×3 = .1875 Watts  

(Answer: (2) 0.187 W)