Question

Power of thin converging lens(1.5) is +5D. This lens is dipped in a liquid of refractive index nu. If it behave like diverging lens of focal length 100 cm then find nu.​

Answer 1

Explanation:

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Answer 2

Explanation:

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♡ ↪Given,

For convergent lens,

μ

a

=1, refractive index of air

μ

g

=1.5, refractive index of glass

P

C

=+5D

the Power of the lens is given by the lens maker formula

P

C

=

f

1

=(

μ

a

μ

g

−1)(

R

1

1

−

R

2

1

)=+5D. . . . . .(1)

Now, When convergent lens immersed in a liquid of refractive index μ, convergent lens act as a diverging lens of focal length −100cm

By lens maker formula,

P

d

=

f

1

=(

μ

μ

g

−1)(

R

1

1

−

R

2

1

)=

100

−100

=−1D. . . . . . (2)

Divide equation (1) by equation (2), we get

P

d

P

C

=

μ

μ

g

−1

(

μ

a

μ

g

−1)

=−5

μ

1

μ

g

=−5(

μ

μ

g

−1)

1

1.5

−1=−5(

μ

1.5

−1)

5

0.5

=−(

μ

1.5

−1)

μ=

3

5

♡

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