Math, asked by rubi8363, 7 months ago

pozzz solve the problem​

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Answers

Answered by BrainlyEmpire
2

Correct Question-:

  • The length and breadth of a rectangle are 11 cm and 9 cm . Find its area and perimeter ?

AnswEr -:

  • \boxed{\blue{\sf{\star{\:Perimeter \:of\:Rectangle \:is\:40 cm}}}}
  • \boxed{\blue{\sf{\star{\:Area  \:of\:Rectangle \:is\:99 cm²}}}}

Explanation-:

Given ,

  • The length of Rectangle is 11 cm .
  • The breadth of Rectangle is 9 cm .

To Find ,

  • The area and perimeter of Rectangle.

☆ Figure related to the question-:

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 11 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 9 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}

Solution-:

  • \boxed{\blue{\sf{\star{\:Perimeter \:of\:Rectangle \:is\:2(length+ breadth)}}}}

Here ,

  • The length of Rectangle is 11 cm .
  • The breadth of Rectangle is 9 cm

Now ,

\pink{\sf{\rightarrow {Perimeter \: of\: Rectangle  \:-: 2( 11+ 9 ) }}}

\pink{\sf{\rightarrow {Perimeter \: of\: Rectangle  \:-: 2( 20 ) }}}

\pink{\sf{\rightarrow {Perimeter \: of\: Rectangle  \:-: 40 cm  }}}

Therefore,

\boxed{\purple{\sf{\star{\:Perimeter \:of\:Rectangle \:is\:40 cm}}}}

Now ,

\boxed{\blue{\sf{\star{\:Area \:of\:Rectangle \:is\:length\times breadth}}}}

Here ,

The length of Rectangle is 11 cm .

The breadth of Rectangle is 9 cm.

Now ,

\pink{\sf{\rightarrow {Area \: of\: Rectangle  \:-: (11 \times9 ) }}}

\pink{\sf{\rightarrow {Area \: of\: Rectangle  \:-: 99 cm²  }}}

Therefore,

.

\boxed{\purple{\sf{\star{\:Area  \:of\:Rectangle \:is\:99 cm²}}}}

Hence ,

\boxed{\purple{\sf{\star{\:Perimeter \:of\:Rectangle \:is\:40 cm}}}}

\boxed{\purple{\sf{\star{\:Area  \:of\:Rectangle \:is\:99 cm²}}}}

_________________________________________

Answered by Anonymous
50

Given :-

  • Length ( l ) = 11cm

  • Breadth ( b ) = 9cm

Solution :-

Perimeter of rectangle = 2(l+b)

P = 2(11+9)

P = 2(20)

Perimeter = 40cm

Area of rectangle = l × b

A = 11×9

Area = 99cm²

Hence , perimeter is 40cm and area is 99cm².

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