Question

PQ and PR are tangents to a circle with centre O such that angleQPR=50degree.then angleOQR is equal to=

Answer 1

Answer:

∠ OQR= 25°

Step-by-step explanation:

As sum of all sides of quadrilateral is 360,

∠QPR+∠QOR+∠PQO+∠RQO=360°

50+∠QOR+90+90=360

∠QOR=130

OQ=OR...... radii of a circle

∴∠ OQR=∠ORQ=x

sum of all sides of triangle is 180

x+x+130=180

2x=50

x=25°

∠ OQR=25°

Answer 2

Answer:90°

Step-by-step explanation:

PQ ⊥ OQ =Tangent⊥Radius

∴angleOQR=90°