PQ and PR are two tangent with centre O, Such that angle QPR=50°.Then find angle OQR.
(a)25°
(b)30°
(c)40°
(d)50°
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hello friend,
as angle P + O = 180* so angle O= 130*
so angle O= 130 *and angle QRO = RQO
So in triangle ROQ
angle ROQ+ RQO+QRO=180*
angleRQOX2=50*
angle RQO=25*
as angle P + O = 180* so angle O= 130*
so angle O= 130 *and angle QRO = RQO
So in triangle ROQ
angle ROQ+ RQO+QRO=180*
angleRQOX2=50*
angle RQO=25*
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