the hypotenuse of a right triangle is 4 times the smallest side. The third side is root 735. find the hypotenuse and the smallest side.
Answers
Answered by
43
lets the smallest side be x. Then hypotenuse is 4x.
So, by Pythagoras theorem
x^2+735=(4x)^2
735=16x^2-x^2
x^2=735÷15
x=_/49
x=7cm
So, smallest side is 7cm and hypotenuse is 28cm.
PLZ MARK IT AS BRAINLIEST.
So, by Pythagoras theorem
x^2+735=(4x)^2
735=16x^2-x^2
x^2=735÷15
x=_/49
x=7cm
So, smallest side is 7cm and hypotenuse is 28cm.
PLZ MARK IT AS BRAINLIEST.
Answered by
13
Hi friend,
ATQ let the smallest side =x,
so hypotenuse =4x
and third side =√735
NOW using PGT,we get
(4x)²=x²+(√735)²
16x²=x²+735
15x²=735
x²=735/15
x²=49
x=7
so small side=7cm
and hypotenuse=28 cm
__________________________________________________________________________________________________________________________
ATQ let the smallest side =x,
so hypotenuse =4x
and third side =√735
NOW using PGT,we get
(4x)²=x²+(√735)²
16x²=x²+735
15x²=735
x²=735/15
x²=49
x=7
so small side=7cm
and hypotenuse=28 cm
__________________________________________________________________________________________________________________________
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