Question

Pq and pt are tangents to a circle with centre o and radius 5 cm if pq = 12 cm then prove that the perimeter of the quadrilateral pqot is 34 cm

Answer 1

Step-by-step explanation:

Given: PQ and PT are tangents to the cirle with centre O, and radius = 5 cm

Two tangents to a circle can only be drawn when the point lie outside of the circle. So, point P lies out side of the circle

Since tangents drawn from an external point to a circle are of equal length.

Therefore,

PQ = PT = 12 cm

Radius OQ = OT = 5 cm

Now,

Perimeter of quadrilateral PQOT = PQ + PT + OQ + OT

=12 + 12 + 5 + 5

= 34 cm

Thus,

Perimeter of quadrilateral PQOT = 34 cm

Hence Proved.

Answer 2

Answer:

Hey mate! Here's your answer:

Step-by-step explanation:

PQ and PT = 12 cm as the tangents of a circle are equal.

Radius is 5 cm.

So OQ and OT = 5 cm.

So perimeter = PQ + OQ + OT + PT = 12 + 12 + 5 + 5 = 34 cm.

Hence proved!

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