PQ and RS are two parallel chords of a circle whose centre is O and radius is 10 cm. If PQ = 16 cm and RS= 12 cm, find the distance between PQ and RS, if they lie
(i) on the same side of the centre O.
(ii) on the opposite sides of the centre O.
Answers
Answered by
0
Answer:
The correct option is B
14 cm
PQ = 16cm
⇒
P
L
=
L
Q
=
8
c
m
[ the perpendicular from the centre of the circle bisects the chord]
△
O
Q
L
is a right angled triangle.
∴
O
L
2
=
O
Q
2
−
Q
L
2
=
10
2
−
8
2
= 100 - 64 =
Attachments:
Similar questions