Question

PQ is a chord of a circle with center O and PT is a tangent.If QPT=60°,find PRQ

Answer 1

Given, PQ is a chord of a circle with center O. Also, ∠QPT = 60°.

let x be the point on the tangent PT.

Now, ∠QPT + ∠QPX = 180°  [Linear pair]

⇒ ∠QPX = 180° - ∠QPT = 180° - 60° = 120°

Again, ∠QPX = ∠PRQ  [Alternate segment theorem]

⇒ ∠PRQ = 120°

NEXT TIME REMEMBER TO GIVE THE FIGURE PLZ